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递归反转链表改变原链表吗
Solution:
解:
Algorithm to find length
查找长度的算法
Input:
输入:
A whose address of the first node is stored in a pointer, say head.
一个 ,其第一个节点的地址存储在指针(例如head)中。
Output:
输出:
The no of nodes in the list, c
列表中的节点数c
Data structure used:
使用的数据结构:
Singly linked list where each node contains a data element say data, and the address of the immediate next node say next, with head holding the address of the first node.
单链列表,其中每个节点包含一个数据元素,例如data ,直接下一个节点的地址说next ,头保持第一个节点的地址。
Pseudo code:
伪代码:
Begin temp=head c=0 //counter to store count of nodes While(temp!=NULL) //upto end of linked list begin c=c+1 temp=temp->next End whileEnd
C code:
C代码:
#include#include //node sructuretypedef struct list { int data; struct list *next;}node;int length(node *temp);int main(){ node *head=NULL,*temp,*temp1; int choice,count; //building linked list do { temp=(node *)malloc(sizeof(node)); if(temp!=NULL) { printf("\nEnter the element in the list : "); scanf("%d",&temp->data); temp->next=NULL; if(head==NULL) { head=temp; } else { temp1=head; while(temp1->next!=NULL) { temp1=temp1->next; } temp1->next=temp; } } else { printf("\nMemory not avilable...node allocation is not possible"); } printf("\nIf you wish to add more data on the list enter 1 : "); scanf("%d",&choice); }while(choice==1); //Now counting the length of the list using a user defined function count=length(head); printf("\nThe length of the list is : %d",count); return 0;}//function to find length iterativelyint length(node *temp) { int c=0; //travarsing to the end of the list and count the number of nodes while(temp!=NULL) { c=c+1; temp=temp->next; } return c;}
Output
输出量
Enter the element in the list : 1If you wish to add more data on the list enter 1 : 1Enter the element in the list : 2If you wish to add more data on the list enter 1 : 1Enter the element in the list : 3If you wish to add more data on the list enter 1 : 1Enter the element in the list : 4If you wish to add more data on the list enter 1 : 1Enter the element in the list : 5If you wish to add more data on the list enter 1 : 0The length of the list is : 5
翻译自:
递归反转链表改变原链表吗
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